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2x^2-9.5x-2.5=0
a = 2; b = -9.5; c = -2.5;
Δ = b2-4ac
Δ = -9.52-4·2·(-2.5)
Δ = 110.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9.5)-\sqrt{110.25}}{2*2}=\frac{9.5-\sqrt{110.25}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9.5)+\sqrt{110.25}}{2*2}=\frac{9.5+\sqrt{110.25}}{4} $
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